Question

Help?

Answer 1

so for the first triangle perimeter, p1, is ;

p1 = 2y + x = 14

for the second triangle perimeter, p2, is;

p2 = (5/4)y + (5/4) y + 3x = 21

p2 = (5/2)y + 3x

so you need to solve the simultaneous equations
2y + x = 14
(5/2)y + 3x

Answer 2

the bottom one should be

(5/2)y + 3x = 21

Answer 3

Okay, how would I solve those?

Answer 4

you need to get just one variable in an equation first. So i would eliminate the x's by multiplying the top equation by 3. Now both equations have "3x" and you can subtract the top equation from the bottom to get a formula with just y's.

Answer 5

Okay.

Answer 6

then you can solve that to find the value of y, plug it back in the original equation and you can find out x

Answer 7

Thanks.