a baseball is thrown at a 23 degree angle with an initial speed of 19.5m/s. if the player stands 1.3m tall. what is the total time spent in the air by the ball?
|dw:1358382582189:dw| your only interested in velocity in the h direction
which you can work out since you know the angle|dw:1358382704182:dw|
then once you know the velocity upwards you can calculate the time easily since there is only once source of acceleration, gravity. x = x_0 + ht + (1/2)gt^2 where x_0 is original position (1.3m) ht is the original velocity in the up direction (h) times by the time (t) and g is the acceleration due to gravity (9.81 m s^-2) if you set x = 0 ( you want to know the time at the floor i.e. when x = 0, then you will be able to use the quadratic formula to find t
dude thank you so much...hold on let me try and review this
may you work further? please i think i undrstand
where are you up to
i'm sorry if i'm insulting you but..i think i have a great physics teacher because she explains it sooo easy! you..make it seem so difficult..like i really cant understand this. i knew how to do these problems but i forgot how to..could you just tell me the answer?...wait...crap ineed like a little chart thing
dude i'm just so confused..
yeah sorry i couldnt help you more
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