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Chemistry 14 Online
OpenStudy (anonymous):

Elements in the third period make compounds with oxygen as follows: What are the compounds for Mg and P MgO2 and P2O3 MgO and PO3 Mg2O and PO2 MgO and P2O5 MgO2 and P2O5 Mg2O2 and PO3

OpenStudy (anonymous):

\[2Mg + O_{2} \rightarrow 2MgO\] Magnesium Oxide

OpenStudy (anonymous):

thats not what i need but thank you for trying

OpenStudy (anonymous):

Are you looking for which choice combination is correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Based off of what is given, I'd say right now you have either choice 1 or 5. I'm thinking about P & O right now...

OpenStudy (anonymous):

1 and 5 are actually incorrect, the homework program i am using says so :(

OpenStudy (anonymous):

Really? I'll hit the books again...

OpenStudy (anonymous):

thank you so much!

OpenStudy (anonymous):

You know what, I looked at my answer in the incorrect way. I believe it could be eliminated down to either choices 2 or 4 because my "dyslexia" kicked in. The 2 in front of the products implies that there are two molecules needed. I made a mistake in placing it with the oxygen. Still thinking about the P & O though...

OpenStudy (anonymous):

haha no problem

OpenStudy (anonymous):

After further thought I believe choice 4 is the correct answer. If we look at the lewis structure of oxygen and phosphorus, we see that oxygen has 6 available electrons per atom and the phosphorus only 5 available electrons. By drawing an ugly picture we can see that each phosphorous electron pair can complete the octet for 2 oxygens per phosphorus and still have one electron left over for each phosphorus. These 2 remaining electrons would then go to a 5th oxygen atom and provide a perfect octet of electrons for the last oxygen atom and there would then be no extra electrons left. (Drawing ugly picture now...)

OpenStudy (anonymous):

we haven't covered lewis structures yet but ok

OpenStudy (anonymous):

It wants to obey the octet rule. This means that no electrons are left out if possible. If there is a vacant place to go they will fill it. Check out the ugly drawing. Maybe it will make sense. The file is a PDF. Let me know how that works for you.

OpenStudy (anonymous):

And again, when I mean octet rule, I mean that each atom only has 8 electrons that It can have in its outer shell.

OpenStudy (anonymous):

haha that's pretty good

OpenStudy (anonymous):

my teacher told us about how Li and Cl combine: LiCl and how Be and Cl combine: BeCl2 but once i get to the period that P is in i get confused

OpenStudy (anonymous):

Do you know how to identify if the element has a positive or negative charge associated with it? That helps a lot and I can explain briefly if needed.

OpenStudy (anonymous):

yes it comes from the periodic table right?

OpenStudy (anonymous):

Yep. Your first group under hydrogen/lithium has a charge of +1. The berellyum (Be) group has a charge of +2, the Boron group +3, and Carbon +4. Going in the other direction, the Halogens (Fluorine, Chlorine, etc...) have a charge of -1, Oxygen group (-2), Nitrogen group (-3). Lets consider the reaction between aluminum and chlorine. Aluminum has a +3 Charge and chlorine a -1 Charge. I'll post the equation below and talk further about this.

OpenStudy (anonymous):

Actually, lets consider Aluminum and Oxygen (-2). One sec...

OpenStudy (anonymous):

\[Al ^{+3} + O ^{-2} \rightarrow Al _{2}O _{3}\]

OpenStudy (anonymous):

so they just switch?

OpenStudy (anonymous):

This is an ionic type equation because we are only looking at how they combine. What you do is take...

OpenStudy (anonymous):

Yep, they switch.

OpenStudy (anonymous):

Make the "exponent" the subscript of the combining atom.

OpenStudy (anonymous):

Or element I should say.

OpenStudy (anonymous):

This is the basis for making chemical equations but a few more things really need to be done to balance them but you're right for what you're being taught now... They just switch.

OpenStudy (anonymous):

so what happens when you have 2 negative charges that are not the same?

OpenStudy (anonymous):

Example?

OpenStudy (anonymous):

N and O

OpenStudy (anonymous):

i can only choose one answer

OpenStudy (anonymous):

keep in mind only one of each element is being combined into a compound

OpenStudy (anonymous):

Same Idea as with the phosphorous. Both nitrogen and phosphorous have 5 electrons and 3 spaces to be filled. Oxygen has 6 electrons and 2 spaces to be filled, again according to the octet rule. When you are combining negative charged elements, we are dealing with covalent bonding. So to have all of the electrons filled, you would have to draw a lewis structure like I did earlier and you would find that the end result would be N205

OpenStudy (anonymous):

it was the fourth answer!!! :D thank you so much!!!!!!

OpenStudy (anonymous):

No problem. Thanks for the props... Metallic bonding takes place between the metals and non metals on the periodic table. This is when you can just switch things. Covalent bonding is a little more tricky. Good luck and thanks again!

OpenStudy (anonymous):

no, thank you! i am sure i will have more questions for u in the future. r u a chemistry teacher?

OpenStudy (anonymous):

I'm actually a HS Physics & Math teacher working on my Chem certification. By all means look me up. I need the extra practice.

OpenStudy (anonymous):

Cool! I'm sure you will be a great Chemistry teacher as well!

OpenStudy (anonymous):

Thanks for the kind words. Take school seriously. The benefit may not be seen now but the reward is yours to be had in the future. I'm off to bed. Good luck!

OpenStudy (anonymous):

I will! Thank you so much!

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