Question

Determine the angle between the pipe segments BA and BC.

Answer 1

Here's the link to the drawing:
http://session.masteringengineering.com/problemAsset/1521197/3/Hibbler.ch2.p130.jpg

Answer 2

Find the length of the pipe segments and the line connecting them. Then apply the law of cosines.

Answer 3

But how can you show me?

Answer 4

Is the answer 48.2?

Answer 5

The length of a line segment is given by \[l = \sqrt{(x _{1}-x _{2})^{2}+(y _{1}-y _{2})^{2}+(z _{1}-z _{2})^{2}}\]

Law of cosine is \[a ^{2}= b ^{2}+c ^{2}-2bc \times \cos \alpha \] where a,b,c are the lengths of the sides of a triangle and alpha is the angle opposite side "a" .

Answer 6

Well I know the process I just don't know how t get x, y and z. I have trouble getting them for some reason (mixed up). Thanks anyways.

Answer 7

find the coordinates of the end point of each pipe x,y,z look at the diagram, the distances from the origin are given for each eg the pt B is at 3,4,0 right? what is A ? easy, what is C ? and plug into formula for l.

Answer 8

Are you talking about AB for 3,4,0?

Answer 9

x1,y1,z1 = 3,4,0 are the coordinates of pt B. coor of A=?

Answer 10

coordinates of a is 4,2,4?

Answer 11

No, it is at the origin therefore 0,0,0.

Answer 12

So the length is 5. Do I have to find the coordinates of c too?

Answer 13

yes to both.

Answer 14

Done. Took awhile but thanks anyways.

Answer 15

I'm glad to have been of assistance.