Question

1/(b^{-2}+a^{-2})= b^{2}+a^{2}

True or False?

Answer 1

oh no

Answer 2

left hand side is
\[\frac{1}{\frac{1}{b^2}+\frac{1}{a^2}}\]

Answer 3

ohh that makes sense
is it mainly because their being added?

Answer 4

you could get rid of this complex fraction by multiplying top and bottom by \(a^2b^2\)

Answer 5

you would get
\[\frac{a^2b^2}{a^2+b^2}\] which is certainly not \(a^2+b^2\)

Answer 6

oh ok

Answer 7

thanks satellite 73

Answer 8

yw