How can I find the vertex in the standard form of quadratic function: y = 2x^2 + 5 ? i don't understand because there's no b value

Question

aravindg · Answer

b=0 here

kirbykirby · Answer

WHat do you use as "b" in the standard form? What did your tell you what the standard form was with your notation?

anonymous · Answer

y-5=2x^2
if we put y-5=Y  and x-0 =X
we have the standard form as X^2=1/2 Y

 X^2=4*(1/8) Y
hence reqd vertex is 0,5

anonymous · Answer

it's using the standard form f(x) = ax^2 + bx + c

kirbykirby · Answer

Ok so as @AravindG said, b=0 because ax^2+0x+c = ax^2 +c, and here a = 2, and c=5

aravindg · Answer

yep here it will be 

$$y=2x^2+0x+5$$

anonymous · Answer

thank you so so much

aravindg · Answer

yw :)