Question

sec 240 degrees

Answer 1

sec 240=sec 270-30

Answer 2

its -2 but i don't know what to use to get there?

Answer 3

right but its 1/cos..

Answer 4

or wait nvm...im gonna try it

Answer 5

1/cos(270-30) =1/cos(3*90 -30)

Answer 6

cos 270-theta=-sin theta

Answer 7

is this true:
sec(u-v)=sec u sec v + csc u csc v

Answer 8

so here it will be nothing but

\[\dfrac{-1}{\sin 30 }\]

Answer 9

why should u think of that when u hav straight method available?

Answer 10

:)

Answer 11

i know but im trying to make sense of it in my head

Answer 12

@ghazi

Answer 13

@sauravshakya

Answer 14

1/cos(270-30) =1/cos(3*90 -30)=1/(-sin30)

Answer 15

oh wait yes ^ that makes more sense

Answer 16

make a reading of this for future clarity

http://www.sparknotes.com/math/trigonometry/trigonometricfunctions/section4.rhtml