Question

N.

Answer 1

try substituting each points , the zeros of the equation is actually the solution of the equation

Answer 2

and x^3 being present do you think what i am thinking? :)

Answer 3

haha @hartnn great minds think alike :)

Answer 4

lol .

Answer 5

@hartnn you fell into the trap! read the problem statement again

Answer 6

O.o
there can be 2 complex roots....

Answer 7

REAL gosh !

Answer 8

i go with my first reply :)

Answer 9

and there is!

Answer 10

@AravindG I tried your method and I got d?

Answer 11

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Answer 12

you are right !

Answer 13

This problem illustrates the importance of reading carefully, instead of seeing what you expect...