Simplify:
√128x^5y^2
Show work pleasee(:

Question

Simplify: 
√128x^5y^2
Show work pleasee(:

blurbendy · Answer

Sqrt[128x^5y^2] = 
8x^2y√2

blurbendy · Answer

oops

blurbendy · Answer

8x^2y√2x

anonymous · Answer

does it help to know that $128=2^7$ ?

anonymous · Answer

you are taking the square root of $2^7x^5y^2$ and you do this in your head
2 goes in to 7 3 times with a remainder of 1 so $2^3$ comes out of the radical, one $2$ stays in
2 goes in to 5 two times with a remainder of 1, so $x^2$ comes out and one $x$ stays in
2 goes in to 2 once, so $y$ comes out
you get 
$$2^3x^2y\sqrt{2x}$$

anonymous · Answer

There aren't 2 numbers that multiply to be 128... I don't think

anonymous · Answer

$128=2^7$

anonymous · Answer

it should also be pretty clear that since 128 is even, it must be two times something 
half of 128 is 64, so it is $128=2\times 64$

anonymous · Answer

Oh! Okay thank you

anonymous · Answer

@itsallycatt see if you can understand the method i wrote above, it will make your life much simpler when you do these. it is a lot of words, but that is because i was trying to write what i was actually thinking.  it is not hard to  understand