1/4x - 1/5 (x-4)= 5x looking for where to start
Hint: \[\frac{1}{4}x - 5x = \frac{1}{5}(x-4)\]
\[\frac{1}{4}x - 5x = \frac{1}{5}x - \frac{4}{5}\]
\[\frac{1}{4}x - 5x - \frac{1}{5}x = - \frac{4}{5}\] \[\left(\frac{1}{4} - 5 - \frac{1}{5}\right)x = - \frac{4}{5}\]
ok
\[-\frac{99}{20}x = - \frac{4}{5}\] \[ \frac{4}{5} =\frac{99}{20}x\]
I hope that (x - 4) term wasn't in the denominator of the fraction.
no, it wasnt
Okay, so then, you should be able to figure things out from there.
unfortunately, that is where I got stuck
i ended up with -83/20 = x
which was wrong
Well of course. x isn't negative.
I tried to show that in my very last entry.
lol, it can be in my math world..... my daughter tells me the math police are going to arrest me for breaking math laws...
But 88/20 isn't the right value anyway.
And even if it was, you'd still have to reduce it to lowest terms.
no, 83
4/5 = 16/20
and when you subtract the 99/20 from the right and do the same to the left, I came up with -83/20
You don't subtract 99/20 from both sides.
You have to multiply both sides by 20/99 to isolate x. Then afterwards, reduce.
awwww and come up with 16/99!
Congrats, you found the correct answer.
with much in-trepidation
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