Graph the function, not by plotting points, but by starting from the graphs in the figures below. State the domain, range, and asymptote.
y = 1 + log3 x

Question

anonymous · Answer

Uhhh what?

anonymous · Answer

Everyone is welcome on this site.

anonymous · Answer

it is $y=1+\log_3(x)$ ?

anonymous · Answer

you cannot take the log of a non - positive number, so domain is 
$$(0,\infty)$$

anonymous · Answer

range of log is all real numbers, so range of $1+\log_3(x)$ is also all real numbers $\mathbb{R}$

anonymous · Answer

there is no horizontal asymptote, but there is a vertical asymptote at $x=0$ as the function goes to $-\infty$ as $x\to 0$

anonymous · Answer

here is a nice picture, make sure you click on "real valued plot" because wolfram will give you the complex log if you are not careful http://www.wolframalpha.com/input/?i=1%2Blog%28x%29

anonymous · Answer

actually, here is one for $y=1+\log_3(x)$ http://www.wolframalpha.com/input/?i=1%2Blog_3%28x%29