Find a quadratic function in standard form that has the following points: (1, -2); (2, -2); (3, -4).

Question

Find a quadratic function in standard form that has the following points:  (1, -2);  (2, -2);  (3, -4).

tkhunny · Answer

Can you find the Axis of Symmetry without doing any algebra?

anonymous · Answer

im not sure

tkhunny · Answer

Shall we guess that (0,-4) is yet another point?

tkhunny · Answer

Axis of Symmetry is x = 3/2.  Please tell me why?

tkhunny · Answer

Quadratic Function in Standard Form:  $f(x) = ax^{2} + bx + c$

From your three points:

(1, -2);  (2, -2);  (3, -4).

We have:

$f(x) = a(1)^{2} + b(1) + c = -2$
$f(x) = a(2)^{2} + b(2) + c = -2$
$f(x) = a(3)^{2} + b(3) + c = -4$

And you have some algebra in your future!