Question

Find the period of the function.

y = 5 cos 1/2 x

Answer 1

@Butterfly16

Answer 2

answer choices are 4 pi and 5

Answer 3

@Yahoo! @zepdrix

Answer 4

Okay, I'll show you. :o) Hold on

Answer 5

f(x)= a sin(bx-x)+d

to find the period: 2pi/b

so 2pi/1/2. Do you know how to solve it? :o)

Answer 6

not exactly

Answer 7

When you have two fractions, like this, you take the inverse of 1/2, which is 2/1 or 2 and multiply it by 2pi, which gives you what? :o)

\[2*2\pi\]

Answer 8

so its 4pi?

Answer 9

\[\frac{ 2\pi }{ \frac{ 1 }{ 2 } } \rightarrow 2\pi *\frac{ 2 }{ 1 }\rightarrow 2\pi*2\]

Awesome job! :o)

Answer 10

thankyou andcan you help me with this last one too? Identify intervals on which the function is increasing, decreasing, or constant.

g(x) = 2 - (x - 7)^2

Answer 11

the answer choices are
Increasing: x < -7; decreasing: x > -7

Increasing: x < 7; decreasing: x > 7

Increasing: x > 2; decreasing: x < 2

Answer 12

I'm not sure how to solve it, but if you graph it, see where the value of x increases and where the value of x starts to decrease.

Answer 13

i got b

Answer 14

Well, if you look at it, when the graph is increasing (or going up) x equals these numbers: -7, -2, 1, 2. When the graph hits 2, the x values turn to: 2, 1, -2, -7. See how the value of x increases on the left side of the graph and then starts decreasing again on the right after it turns at 2?