Question

Divide 2x^2 + 17x + 35 by x + 5.
A. x + 7
B. 2x + 7
C. x + 27
D. 2x + 27

Answer 1

so this is really

\[\frac{(2x^2 + 17x + 35)}{(x + 5)}\]

can you factor the numerator..?

Answer 2

No, there is no GCF.

Answer 3

yes there is... do you know how to factorise a quadratic..?

Answer 4

no

Answer 5

I have a better idea for you,

Use Synthetic division method.

Answer 6

the factors of this are of the form

(2x + a )(x + b)

where a * b = 35 and 2a + b = 17

Answer 7

why not just factorise

\[\frac{(x + 5)(2x + 7)}{(x + 5)}\]

Answer 8

sorry 2b + a = 17

Answer 9

yes - its easier to just factorise if you are competent at this

Answer 10

so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?

Answer 11

right

Answer 12

thats correct... easy if you can factor..

Answer 13

Okay, thanks!