Question

simple algebra.

Answer 1

hey, simply dont understand this: \[\frac{ \sqrt{x} }{ x } = \frac{ 1 }{ \sqrt{x}}\]

Answer 2

A couple of ways you can get that result:
Canceling common terms in a fraction:
\[\sqrt{x}*\sqrt{x} = x\]\[\frac{\sqrt{x}}{x} = \frac{\sqrt{x}}{\sqrt{x}*\sqrt{x}} = \frac{1}{\sqrt{x}}\]
Exponents:
\[\sqrt{x} = x^{1/2}\]\[\frac{x^a}{x^b} = x^{a-b}\]\[x^{-n} = \frac{1}{x^n}\]\[\frac{\sqrt{x}}{x} = \frac{x^{1/2}}{x^1} = x^{(1/2)-1} = x^{-1/2} = \frac{1}{x^{1/2}} = \frac{1}{\sqrt{x}}\]

Answer 3

thanks so much mate!