Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (dumbsearch2):

Solve the following system using the substitution method: 3x + y = -3 y = 2x + 7

OpenStudy (dumbsearch2):

Thanks so much! :)

Parth (parthkohli):

Because you know that \(y = 2x + 7\), you can rewrite \(3x + \color{#C00}{y}\) as \(3x + \color{#C00}{2x + 7}\). Now\[3x + 2x + 7 = -3\]Can you solve this?

OpenStudy (dumbsearch2):

yeah x = -2 right? so which answer would it be? thanks. :)

Parth (parthkohli):

Okay, so because \(x = -2\), we know that \(y = 2x + 7\) can be written as \(y = 2(\color{#C00}{-2}) + 7\)

OpenStudy (dumbsearch2):

so which answer is it? (Sorry, I don't quite get it... :() Like which should I put in as "x" ,and which as "y"? In the coordinates box? See attached...

Parth (parthkohli):

(x,y)

OpenStudy (dumbsearch2):

yes, what is the answer? what should I put in (x,y)? thanks. :)

Parth (parthkohli):

What do you get for \(x\) and \(y\)? :-)

OpenStudy (anonymous):

do you work them out individually and add them?

Parth (parthkohli):

Wait, are you awn786?

OpenStudy (anonymous):

ye

OpenStudy (dumbsearch2):

no I'm not??

OpenStudy (anonymous):

oohh i get it

Parth (parthkohli):

LOL okay

OpenStudy (dumbsearch2):

Waa?

OpenStudy (anonymous):

what about me @ParthKohli

Parth (parthkohli):

\[x = -2 \ \ \ \& \ \ \ y = 2(-2) + 7\]

OpenStudy (dumbsearch2):

Thnks! :)

Parth (parthkohli):

What is \(2(-2) + 7\)?

OpenStudy (anonymous):

what about me @ParthKohli

OpenStudy (dumbsearch2):

3, right?

Parth (parthkohli):

Yes. So you have \(x = -2\) and \(y = 3\).

OpenStudy (dumbsearch2):

THANK YOU SO MUCH!!! ;) :D

Parth (parthkohli):

We always write the solutions like \((\mbox{solution for x, solution for y})\).

Parth (parthkohli):

So \((-2,3)\)!

OpenStudy (dumbsearch2):

right I know that. :)

OpenStudy (dumbsearch2):

THANKS SO MUCH!!! :D

Parth (parthkohli):

Yay!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!