Solve: 1+[x]=[px].
Solve for x ?
yep. sorry...forgot to mention.
Is that absolute value of x -> |x|
nope...it's the...well...the biggest integer number smaller than x
Well...looks like only in my country we do it like that. For example: [ sqrt(2) ] = [ 1,4142... ] = 1 [ -5/2 ] = [ -2,5 ] = -3
The absolute value isnt the distance between the point on the axis and the origin of it?
Let me get back to the problem, 1+[x]=[px] 1)Subtract both sides by [x]
@Underliner Start working.
well...supposed to write here? 1= [px] - [x]
Right now take [x] common and show me what you are left with.
1= [x] * ([p]-[x])
Try doing it again.
The last eq? Or the whole problem?
Because i started the whole problem again...xD
From 1= [x] * ([p]-[x])
I am assuming "p" is an integer ?
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