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Mathematics
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OpenStudy (anonymous):
Solve: 1+[x]=[px].
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OpenStudy (hba):
Solve for x ?
OpenStudy (anonymous):
yep. sorry...forgot to mention.
OpenStudy (hba):
Is that absolute value of x -> |x|
OpenStudy (anonymous):
nope...it's the...well...the biggest integer number smaller than x
OpenStudy (anonymous):
Well...looks like only in my country we do it like that.
For example:
[ sqrt(2) ] = [ 1,4142... ] = 1
[ -5/2 ] = [ -2,5 ] = -3
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OpenStudy (anonymous):
The absolute value isnt the distance between the point on the axis and the origin of it?
OpenStudy (hba):
Let me get back to the problem,
1+[x]=[px]
1)Subtract both sides by [x]
OpenStudy (hba):
@Underliner Start working.
OpenStudy (anonymous):
well...supposed to write here?
1= [px] - [x]
OpenStudy (hba):
Right now take
[x] common and show me what you are left with.
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OpenStudy (anonymous):
1= [x] * ([p]-[x])
OpenStudy (hba):
Try doing it again.
OpenStudy (anonymous):
The last eq?
Or the whole problem?
OpenStudy (anonymous):
Because i started the whole problem again...xD
OpenStudy (anonymous):
From 1= [x] * ([p]-[x])
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OpenStudy (shubhamsrg):
I am assuming "p" is an integer ?
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