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Mathematics 15 Online
OpenStudy (anonymous):

Solve: 1+[x]=[px].

OpenStudy (hba):

Solve for x ?

OpenStudy (anonymous):

yep. sorry...forgot to mention.

OpenStudy (hba):

Is that absolute value of x -> |x|

OpenStudy (anonymous):

nope...it's the...well...the biggest integer number smaller than x

OpenStudy (anonymous):

Well...looks like only in my country we do it like that. For example: [ sqrt(2) ] = [ 1,4142... ] = 1 [ -5/2 ] = [ -2,5 ] = -3

OpenStudy (anonymous):

The absolute value isnt the distance between the point on the axis and the origin of it?

OpenStudy (hba):

Let me get back to the problem, 1+[x]=[px] 1)Subtract both sides by [x]

OpenStudy (hba):

@Underliner Start working.

OpenStudy (anonymous):

well...supposed to write here? 1= [px] - [x]

OpenStudy (hba):

Right now take [x] common and show me what you are left with.

OpenStudy (anonymous):

1= [x] * ([p]-[x])

OpenStudy (hba):

Try doing it again.

OpenStudy (anonymous):

The last eq? Or the whole problem?

OpenStudy (anonymous):

Because i started the whole problem again...xD

OpenStudy (anonymous):

From 1= [x] * ([p]-[x])

OpenStudy (shubhamsrg):

I am assuming "p" is an integer ?

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