Can anyone derive me the formula for the nth term from the Last , of A.P?
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OpenStudy (ash2326):
You want to derive the formula for the nth term of an A.P?
OpenStudy (anonymous):
kk..
OpenStudy (ash2326):
Let the first term be a1
and the common difference be d
now second term will be
a2=a1+d
third term will be
a3=a1+d+d=a1+2d
Do you get this part?
OpenStudy (anonymous):
yes..
OpenStudy (ash2326):
Now if we go on like that,
4th term is
\[a_4=a_1+3d\]
Hence nth term will be
\[a_n=a_1+(n-1)d\]
Do you understand this?
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OpenStudy (anonymous):
yes..and thank u
OpenStudy (anonymous):
one question..why do we add 1 on last step
OpenStudy (anonymous):
because thee are n terms and before we have n-1 terms
OpenStudy (anonymous):
it goes on decreasing such as n, n-1, n-2...
OpenStudy (ash2326):
I don't get you, where do you have doubt?
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OpenStudy (anonymous):
an=a1+(n−1)d, y there is 1
OpenStudy (ash2326):
you mean the 1 in n-1?
OpenStudy (anonymous):
yes.
OpenStudy (ash2326):
for seond term a2, we have d or 1d
for third term a3, we have 2 d
In the formula we have d times ( one no. less than the term no. )
That's why for n we have 1 less than n i.e n-1
OpenStudy (anonymous):
kkk
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