Question

How would I solve this (help would be greatly appreciated :) )
(sqrt(-2x))-(sqrt5-x)=-3/(sqrt5-x)

Answer 1

\[\sqrt(-2x)-(\sqrt5-x)=-3/(\sqrt(5-x))\]

Answer 2

Is this what you have?
\[\sqrt{-2x}-\left( \sqrt{5}-x \right)=\frac{ 3 }{ \sqrt{5}-x }\]

Answer 3

the square root goes over (5-x) not just 5

Answer 4

In both?

Answer 5

\[\sqrt{-2x}-\sqrt{5-x}=\frac{ 3 }{ \sqrt{5-x} }\]

Answer 6

yes

Answer 7

Ok, what if we multiply both sides by \[\sqrt{5-x}\]

Answer 8

on the right, we will be left with (-3)
(Note, I missed the negative)

Answer 9

okay!

Answer 10

On the left we have to distribute so we will mult \[\sqrt{5-x}\]
by \[\sqrt{-2x}\] and by \[\sqrt{5-x}\]

Answer 11

we get:\[\sqrt{-2x \left( 5-x \right)}-\left( 5-x \right)=-3\]

Answer 12

please do look for errors on my part
now, clean up - clear those ( )'s by distributing the neg and mult the expressions in the radical
once all is cleaned up, GET THE RADICAL ALONE ON ONE SIDE

Answer 13

how are we doing?

Answer 14

Good! just doing the distribution. I've got a question though... where did the square root over the -5-x go?

Answer 15

\[\sqrt{5-x} \sqrt{5-x}=5-x\]
It is like squaring a square root - they are opposite operations and undo each other

Answer 16

so we get -(5 - x) which is - 5 + x

Answer 17

oh, okay!

Answer 18

Cpuld you walk me through further?

Answer 19

I've got