Question

someone help me with a few geometry questions please <3

Answer 1

i need to solve 3x + 5 = 10x +2
5 = 7x + 2
idk what to do from here someone please help

Answer 2

Subtract 2 from both sides, then divide both sides by seven. Try that. If that doesn't work, let me know.

Answer 3

ill post the question bc im so lost im trying to catch up on my back work i have till midnight east time and im just getting irritated.

Answer 4

5. In the square ABCD, AE = 3x + 5 and BD = 10x + 2. What is the length of AC ?


2
11
22
32

Answer 5

i get stuck on these stupid problems all the time.

Answer 6

the diagonals are congruent, so AC = BD

furthermore, each diagonal cuts the other diagonal in half, this means

AE = (1/2)*AC

which rearranges to

2*AE = AC

since AC = BD, we can say

2*AE = BD

Answer 7

now plug in the given expressions AE = 3x+5, BD = 10x+2

2*AE = BD

2*(3x+5) = 10x+2

6x + 10 = 10x + 2 ... distribute

10 = 4x + 2 ... Subtract 6x from both sides.

8 = 4x ... Subtract 2 from both sides.

I'll let you finish

Answer 8

okay so x = 2, plugging that in for BD which = AC
10(2)+2= 4... but thats not an option ugh

Answer 9

how does 10*2+2 equal 4?

Answer 10

you just made a silly math error, but that's ok

Answer 11

wait no, 3(2)+5 = 11 nvm lol and i meant 40 but i got it now thank you. can you help me with a couple more?

Answer 12

hopefully you got

AC = BD

AC = 10x+2

AC = 10*2+2

AC = 20+2

AC = 22

Answer 13

yeah i can help with a few more

Answer 14

okay thank you this ones similar, 5x-5=3x+3

5x=3x+7
... i keep getting decimal numbers, blah

Answer 15

5x-5=3x+3

5x = 3x + 8 ... Add 5 to both sides.

2x = 8 ... Subtract 3x from both sides.

x = ???

Answer 16

you just made the error in thinking that 5+3 was 7 when it should have been 8

Answer 17

oh okay well i didnt know since i took the -5 and brought it to the other side if i could take the 3x to the oppisite side. so x=4 right?

Answer 18

you got it, the solution is x = 4

Answer 19

3x is a number like -5 is, so you can add/subtract them to both sides if necessary

Answer 20

okay i will have a few here eventually im trying to do most of them myself, will you be on here for a little while yet?

Answer 21

yes I'll be on if you need more help, but see how far you get

Answer 22

the answer to #5 is actually 22, not 11. i just got that answer correct.