Question

The figure shows the velocity graph of a particle moving along the x-axis (d=9.4, T=2.8). Its initial position is x0 = 3.4 m at t0 = 0 s. At t1 = 1.1 s,

Answer 1

What is the particle's position? What is the particle's acceleration? What is the particle's velocity?

Answer 2

acceleration is slope of the straight line

use v = u + at to find v

and then u can find position

Answer 3

I know that but i dont know which points to plug in?

Answer 4

are you there sorry it took a while to answer back.

Answer 5

would u =3.4 m and t = 1.1s?

Answer 6

no, u hv to choose two points from the graph

i will use 0,0 and 6d,3T

Answer 7

so what do you do after that can you please explain it because i dont understand this problem

Answer 8

slope = y2-y1 / x2 -x1 = 6d - 0 / 3T - 0

Answer 9

so slope = 2d/t

Answer 10

ya, put values of d and t now

Answer 11

ok give me a sec to plug it in

Answer 12

so it would 6.714 m/s^2

Answer 13

so how would you find the velocity and the position now?

Answer 14

hey are you there?