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Given that ABCD is a rhombus, what is the value of x?
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well in your diagram BC is parallel to AD and BD is a transveral so then you can say by alternate angles in parallel lines the base angle is 5x -18 You also need to know the diagonals of a rhombus intersect at right angles |dw:1358830283192:dw| So you can use angle sum of a triangle 180 = 90 +x + 5x -18 just solve the equation for x
how? :)
collect like terms and you will have 180 = 6x + 72 its just a 2 step equation to solve now
Then what? subtract 72 from 180? :)
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thats the 1st step
then what?
well you would have 6x = 108 what do you think you need to do to get a single x ?
divide! which is:18?
thats it well done
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