Question

I need help with a activity.
Part 1:
Euclid’s instructions for constructing an equilateral triangle are:
http://www.google.com/imgres?q=Euclid%27s+two+circle+%2B+triangle&um=
Let the circle BCD with center A and radius AB have been drawn [post. 3], and again let the circle ACE with center B and radius BA have been drawn [post. 3]. And let the straight-lines CA and CB have been joined from the point C, where the circles cut one another, to the points A and B (respectively) [Post. 1].
Re-write the instructions in your own words in numbered form. (Do not copy and paste the from the text)

Answer 1

I have to make it into 3 steps. and Part 2:
The next paragraph is an explanation of why this construction creates an equilateral triangle. Write the explanation in your own words.
And since the point A is the center of the circle CDB, AC is equal to AB [Def. 1.15]. Again, since the point B is the center of the circle CAE, BC is equal to BA [Def. 1.15]. But CA was also shown (to be) equal to AB. Thus, CA and CB are each equal to AB. But things equal to the same thing are also equal to one another [C.N.1]. Thus, CA is also equal to CB. Thus, the three (straight-lines) CA, AB, and BC are equal to one another.

Answer 2

here is the actual word document