Enter the number that would make the following expression a perfect square. x^2-6x+?
For this part would it be 36?
And, Then factor the expression to a squared binomial.

Question

Enter the number that would make the following expression a perfect square. x^2-6x+? 
For this part would it be 36? 
And, Then factor the expression to a squared binomial.

jim_thompson5910 · Answer

you take half of -6 to get -3

then you square it to get 9

so instead of 36 it should be 9

jim_thompson5910 · Answer

it would factor to (x-q)^2 where q is the number that is half of the x-coefficient

jim_thompson5910 · Answer

or i should say (x+q)^2

anonymous · Answer

Okay so would it be (x+9)^2?

jim_thompson5910 · Answer

no it should be (x-3)^2

q = -3 because -3 is half of -6

anonymous · Answer

oh okay! well that makes sense. Thank you!

jim_thompson5910 · Answer

np