Solve kx^2-4x+k=0 Could I get please get a nice neat explanation, these problems make me get stuck.
okay I am here to help you
You need to use the discriminant \[b^2-4ac\]
thanks AZteck I forget what it was called ..
wait that is the quad form right still?
The discriminant comes from the quadratic formula. \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] The discriminant is the expression in the square root as you can see.
yep that is what I was about to type when I had a brain fart lol
because an problem that has a x^2 and =0 we that form to slove
So @AIK \[b^2-4ac=?\] a=k b=-4 c=k Sub in those values in the discriminant and solve for k.
yep that is right sir
I got k=2 is that right?
AIK show me how you got that answer, I want to see the work if you don't mind?
-4^2 -4k^2=0
how do i make a multiply sign?
use your x key
-4^ -4 k(times)k
16-4k^2=0
whoa
b is -4 and a&c are k ?
reminder that is -4 raised to the -4 power not 4^4
but you four -4 fours so the result there is negative
so -4^-4 is what??
b^2−4ac its squared right?
so -4 times -4 would be positive 16
yes it is squared
yes it is 16 postive
so 16 - 4k^2 =0 -> -4k^2= -16 [x-1] -> 4k^2=16 -> k^2= 4 -> k= 2
with the x i mean multiplies
okay that is correct nice job
so why did you say i was wrong o.o?
no I wasn't saying you were wrong, I wanted to see if you knew or were just gueesing is all..
When I help here I try to teach and help students
I am not a teacher myself, just someone that is gifted in math is all
okay then for some reason it made me think i got it wrong somehow, so I went over my math again
no sorry my fault that wasn't the point here. I was trying to get you to do the steps is all. Forgive me next time I will be more clearer on that point okay..
x=+/- 2
yes that is correct :)
You cannot only get a positive value when you square root a number.
You always get a negative value with it as well. Remember that @AIK
Azteck could have done something here better? I feel like AIK thinks I thought he was wrong tips?
I
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