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Algebra 19 Online
OpenStudy (anonymous):

c-3d-2/c-4 d-5

OpenStudy (anonymous):

\[c ^{-3}d ^{-2}/c ^{-4} d ^{-5}\]

OpenStudy (anonymous):

\[c^{-3}=\frac{ 1 }{ c^3 }\] \[d^{-2}=\frac{ 1 }{ d^2 }\] \[c^{-4}=\frac{ 1 }{ c^4 }\] \[d^{-5}=\frac{ 1 }{ d^5 }\]

OpenStudy (anonymous):

Sub in those values and work from there.

OpenStudy (anonymous):

Im new so its hard

OpenStudy (anonymous):

What do you mean you're new and it's hard?

OpenStudy (anonymous):

\[\frac{ (\frac{ 1 }{ c^3 })(\frac{ 1 }{ d^2 }) }{ (\frac{ 1 }{ c^4 })(\frac{ 1 }{ d^5 }) }\]

OpenStudy (anonymous):

Now you can do it. Expand the numerator. And then expand the denominator.

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