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Mathematics 14 Online
OpenStudy (anonymous):

If h(t) represents the height of an object above ground level at time t and h(t) is given by h(t)=-16t2+11t+1 find the height of the object at the time when the speed is zero.

OpenStudy (campbell_st):

ok...you need to differentiate for the velocity do you know how to do that..?

OpenStudy (anonymous):

distance/time ??

OpenStudy (campbell_st):

ok.... so can you find the 1st derivative...

OpenStudy (anonymous):

-32t+11 ?

OpenStudy (campbell_st):

if not there is an alternate method

OpenStudy (campbell_st):

ok... thats good so you need to solve -32t + 11 = 0 this is where the velocity is zero.... then then you have the value of t substitute it into the original equation to get the height..( which will be maximum height) hope this helps...

OpenStudy (anonymous):

okay thank you!!

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