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If h(t) represents the height of an object above ground level at time t and h(t) is given by h(t)=-16t2+11t+1 find the height of the object at the time when the speed is zero.
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ok...you need to differentiate for the velocity do you know how to do that..?
distance/time ??
ok.... so can you find the 1st derivative...
-32t+11 ?
if not there is an alternate method
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ok... thats good so you need to solve -32t + 11 = 0 this is where the velocity is zero.... then then you have the value of t substitute it into the original equation to get the height..( which will be maximum height) hope this helps...
okay thank you!!
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