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Find the following integral
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what is the integer?
\[\int\limits_{}^{} \frac{ (2t+1)^{2} }{ \sqrt{t} } dt\]
does \[\frac{ t ^{2} }{ \sqrt{t} } \] cancel out????
u need to expand of (2t + 1)^2 = 4t^2 + 4t + 1 and convert sqrt(t) = t^(1/2) now, can u simplify (4t^2 + 4t + 1)/t^(1/2) ?
yea i think it does lol
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well I'll show you how far I got \[4 \int\limits_{}^{} \frac{ t ^{2} }{ t ^{1/2} } +4 \int\limits_{}^{} \frac{ t }{ t ^{1/2} } + \int\limits_{}^{} \frac{ 1 }{ t ^{1/2} }\]
so far is good, then use the properties of exponent to simplify of them : |dw:1358987039172:dw|
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