A ball is dropped from rest from a height of 200m. What is the height and velocity of the ball 3 seconds later?

Is this calc-based physics? If so, please walk me through it.

Question

A ball is dropped from rest from a height of 200m. What is the height and velocity of the ball 3 seconds later?

Is this calc-based physics? If so, please walk me through it.

anonymous · Answer

.....no. This is a calculus-based problem, besides gravity's acceleration of 9.81m/s^2 * 200m doesn't make any sense.

raxis · Answer

At first you sounded unsure that it was a calculus-based problem. In any case, I did have it wrong. After 3 seconds it's traveling 29.43 meters per second (multiply the number of seconds by gravity's acceleration. Seconds squared just becomes seconds due to cancellation) Can't say how far it's traveled because it wasn't going that speed the whole time, though.

anonymous · Answer

We actually determined the distance through the equation:$$d=Vi(t)+0.5a*t^2$$ Turns out my friends calculus-based equations and my physics came to the same conclusion. Who knew ;)