Question

The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x?

i) -4
ii) - 1/2
iii) - 1/4
iv) 1/4
v) 1/2

Answer 1

\[x^2=4y^2\]
\[x=2y+1\]
Use substitution.

Answer 2

@amishra try the method suggested above^

Answer 3

I tried, but I am not getting the correct answer :|

Answer 4

Okay...Everytime you see the letter x, substitute this: (2y+1)

Answer 5

\[x^2=4y^2\]
\[(2y+1)^2=4y^2\]

Answer 6

Now you can do it using your knowledge of expanding.

Answer 7

from the eq. x=2y+1 we get, y=(x-1)/2
now x^2=4y^2
=>x^2=4[(x-1)/2]^2=4[(x-1)^2]/4=(x-1)^2=x^2-2x+1
=>2x-1=0
=>x=1/2

Answer 8

@abhrag321 Good job going against the Code of Contact of sharing answers and not actually helping them understand the question.

Answer 9

Code of Conduct*

Answer 10

Its okay. I finally understood my mistake. I was searching for y instead of x :P THANK YOU SO MUCH FOR YOUR HELP!!!!!!!!!!

Answer 11

I have read the Code of Conduct. There is the line,

"Don't provide someone with just the answer - explain the process, and help guide them through understanding the problem."

So please explain the violation process.