Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point
4x-12y=2; (10,-1)

Answer 1

ok, so first my advice would be to put your line equation into standard form. y = mx+b

Answer 2

can you help me with that

Answer 3

yeah,
4x-12y = 2
-12y=2-4x
y = (2/-12)-(4/-12)x

Answer 4

okay thank you and what is next?

Answer 5

?

Answer 6

yeah one sec

Answer 7

ok

Answer 8

ok, so we now know that the equation of the first line is y = (-1/3)x -6.

to find the perpendicular line you have to find the negative reciprocal of the slope
-1/3 to +3

however, since the line has to go through a specific point, the y intercept (-6) changes. therefore, you now have
y = 3x+b

to find b, you plug in the values of (10,-1) for (x,y).

therefore,
10 = 3(-1) + b
10+3 =b
b = 13

therefore, y = 3x +13 is the equation of the line perpendicular to your first line which also goes through (10,-1)

Answer 9

thank you so much

Answer 10

yw