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Mathematics 7 Online
OpenStudy (anonymous):

Prove that 1+sec^2x*sin^2x=sec^2x

geerky42 (geerky42):

Remember, \(\sec^2x = \dfrac{1}{\cos^2 x}\)

OpenStudy (anonymous):

How does that help me?

geerky42 (geerky42):

Replace it then simplify. You will see what I mean.

geerky42 (geerky42):

in 1+sec^2x*sin^2x, of course.

OpenStudy (anonymous):

I got it, sorry for not reporting back to you.

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