someone check my work??
ok
point slope: (5,-6) and (1,-7) first i need to find the slope right? so it's gonna be -1/4 then i plug it in to= y-y2 = m(x-x1) so its: y+7= -1/4(x-5) and the answer is: y= -1/4x - 23/4
positive 1/4
okay! thanks
y = 1/4x - 33/4
for finding the slope, u made an error for the denominator, it's meant to be 1/4
1-5=-4 <<denominator -1/-4 = 1/4
y - y1 = m(x - x1) y - (-7) = (1/4)(x - 1) Now simplify
m = slope = (difference in y)/(difference in x) m = (-6 - (-7)) / ( 5 - 1) = (-6 + 7)/5 = 1/4 Your equation is incorrect, (x1, y1) has to be used, not (x1, y2): y - y1 = m(x - x1), but you must use the x1, y1 of one single ordered pair. Either say x1 = 5, y1 = -6 or x1 = 1, y1 = -7 You can't use the x coordinate of one point with the y coordinate of the other point.
y = 1/4x - 29/4
Correct
gracias
de nada
haha im not spanish btw
neither am I
lol
do you guys know the standard form
0.5x - 2y - 0.75 = 0
rearrange for y=mx +c m=gradient c=y-intercept.
Standard form for a linear equation is ax + by = c where a, b, and c are integers. Just add 0.75 to both sides to get it on the right side. To get integers, multiply both sides by 100
isolate y to be on one side so you find y=....... just like (y=mx +c)
y = 0.5x + (-2y)
yeah?
You asked if we know standard form. Are you trying to write this equation in standard form?
yes but i dont know how to
I just explained. look a few lines up and follow what I wrote.
Here it is again: Standard form for a linear equation is ax + by = c where a, b, and c are integers. Just add 0.75 to both sides to get it on the right side. To get integers, multiply both sides by 100
0.5x - 2y - 0.75 = 0 1) we want it in y=mx+c form so we want y on the LHS and the rest on the RHS. in order to do this we will have to bring the 0.5x and 0.75 to the RHS first. -2y = -0.5x + 0.75 y = ..................... (you can do this)
0.5x - 2y - 0.75 = 0 Add 0.75 to both sides 0.5x - 2y = 0.75 Multiply both sides by 4 to get integer coefficients. 2x - 8y = 3 This is standard form.
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