Here are my two data points (2, 3.5) and (4560, 75). I graphed it on full log graph paper (log log). My equations are log(y) =mlog(x) + log (b). The equation for this line should look like this: y=bx^m. The answer should be very close to this: y=0.88x^2. Can anyone help me find that specific equation to the line, I can not.

Question

hartnn · Answer

did you try to put x=2, y=3.5 first in the equation  log(y) =mlog(x) + log (b) ? 
to get 1 linear equation in m and b....

anonymous · Answer

yeah, I've looked at this several ways. I just can't get the correct answer.

anonymous · Answer

I spoken with some folks at school (fellow students) and apparently, you have to run a matrix on a calculator. Here's the thing, no one ever taught us anything about matrices. I don't even know what one is. It's really an impossible task.

hartnn · Answer

i don't see how matrices can be used here...

anonymous · Answer

I'd love do see how to solve this manually. I know the answer is y=0.88x^2. But I've not gotten anywhere near that.

anonymous · Answer

Actually, my text has 0.87x^1.97 so it need not be exact. When the teacher did this problem 2 weeks ago in class, the answer was the one I posted, however, someone plugged it into a calculator and called out the answer, if I recall. It's a tv based class where you sit in a room on one campus and she's in front of another class in another campus.

anonymous · Answer

Whoa! I just came upon a revelation. My dependent variables (my y values) are 2, and 75!

hartnn · Answer

3.5 and 75 ...

anonymous · Answer

yeah. so my x1 is 2, and my x2 is 4560!

anonymous · Answer

sorry, those are my y1 and y2

anonymous · Answer

yes! I got it. Phew!!!

anonymous · Answer

You bring me such gooood luck Hartn!

hartnn · Answer

just with my presence :P

anonymous · Answer

yessir!

hartnn · Answer

i am glad you got it ^_^