Question

2x-3xy=4-3y solve for y

Answer 1

3xy-3y=2x-4
y(3x-3)=2x-4
then y=(2x-4)/(3x-3)
so x can't be 1
if x=1
we have
2-3y=4-3y which is obviously false
so you get that for each x except x=1, y=(2x-4)/(3x-3)

Answer 2

how did u get from the original equation 2x-3xy=4-3y to 3xy-3y=2x-4

Answer 3

2x-3xy=4-3y multiply by -1
-2x+3xy=-4+3y
then substract -2x from both sides
3xy=-4+3y+2x then substract 3y from both sides
3xy-3y=-4+2x
3xy-3y=2x-4
addition and multiplcation are associative and commutative:
that is a+b=b+a
(a+b)+c=a+(b+c)
also
a*b=b*a
and (a*b)*c=a*(b*c)