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OpenStudy (anonymous):
Anyone understand what I'm being asked here? Find a function f such that f'(x) = x^3 and the line x+y=0 is tangent to the graph of f.
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OpenStudy (anonymous):
so far, as I understand it, they're asking me to find the antiderivative of x^3 whereby f'(x) is x+y=0???
OpenStudy (anonymous):
I mean, this could be anything, right? f(x) = (x^4)/4+2 would work...
OpenStudy (anonymous):
x could then equal -1.
OpenStudy (anonymous):
then x+y=0!
OpenStudy (anonymous):
Do I understand this correctly?
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