Question

Anyone understand what I'm being asked here? Find a function f such that f'(x) = x^3 and the line x+y=0 is tangent to the graph of f.

Answer 1

so far, as I understand it, they're asking me to find the antiderivative of x^3 whereby f'(x) is x+y=0???

Answer 2

I mean, this could be anything, right? f(x) = (x^4)/4+2 would work...

Answer 3

x could then equal -1.

Answer 4

then x+y=0!

Answer 5

Do I understand this correctly?