Question

so the x-intercept of 5y=x+2 is

Answer 1

x-intercept is where y = 0
5(0) = x +2
0 = x + 2
-2 = x

Answer 2

5y=x+2

To find the x-intercept, substitute in 0 for y and solve for x.
5(0)=x+2

Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x+2=5(0)

Multiply 5 by the 0 inside the parentheses.
x+2=5*0

Multiply 5 by 0 to get 0.
x+2=0

Since 2 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2 from both sides.
x=-2

To find the y-intercept, substitute in 0 for x and solve for y.
5y=(0)+2

Remove the parentheses around the expression 0.
5y=0+2

Adding 0 to an expression does not change the value of the expression.
5y=2

Divide each term in the equation by 5.
(5y)/(5)=(2)/(5)

Cancel the common factor of 5 in (5y)/(5).
(<X>5<x>y)/(<X>5<x>)=(2)/(5)

Remove the common factors that were cancelled out.
y=(2)/(5)

These are the x and y intercepts of the equation 5y=x+2.
x=-2, y=(2)/(5)

Answer 3

so: Intercepts
x=-2
y=(2)/(5)

Answer 4

yes.