Can somebody please explain to me how to do this?
A plane takes a trip at 65 mi/h. A plane traveling 30 mi/h makes the same trip in 3 fewer hours. Write and solve an equation to find the distance of the trip.

Question

Can somebody please explain to me how to do this? 
A plane takes a trip at 65 mi/h. A plane traveling 30 mi/h makes the same trip in 3 fewer hours. Write and solve an equation to find the distance of the trip.

hartnn · Answer

you basically need to use just one equation : 
$speed  \times time=distance$

hartnn · Answer

for first plane, whats your equation, can you form it ?

hartnn · Answer

let 1st plane take 't' hours, 
so 2nd plane will take t-3 hours, right ? 
so, the 2 equations you get are : 
65 *t = d
30 (t-3) =d
can you solve these 2 equations for d ?

anonymous · Answer

how can I solve for d if I don't know what t is?

hartnn · Answer

you have 2 equations and 2 unknowns

hartnn · Answer

65 *t = d
30 (t-3) =d
so, put d= 65t from 1st equation into 2nd 
30(t-3) = 65d
find 't' from here,
 then d is just 65t

anonymous · Answer

OHH thank you!!

hartnn · Answer

welcome ^_^