Question

Which ones?!


Which of the following ordered pairs is not a solution to the inequality y ≥ -4x - 2?

A1) (-1, 0)

B1) (0, 0)

C1) (4, 4)

D1) (1, 3)

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Which of the following ordered pairs is a solution to the inequality y ≥ 4x - 2?

A2) (0, -4)

B2) (0, 0)

C2) (0, -3)

D2) (0, -5)

Answer 1

y ≥ -4x - 2
C1) (4, 4)
Put in the x-coordinate (-1) for x and put in the y-coordinate (0) for y. If the inequality is true, then it's a solution.
Is 4 ≥ -4(4) - 2?
0 ≥ -16 - 2
0 ≥ -18
That statement is true, so (4, 4) is a solution. Do the same with the other ordered pairs in both problems.

Answer 2

I have trouble with that kind of stuff..... I'm really really bad at math

Answer 3

Can you follow my example above for choice C1? Try now cgoice A!, (-1, 0).
Insert -1 for x and 0 for y, and see if it makes a true statement.

Answer 4

0 ≥ -4(-1) - 2

Answer 5

0 ≥ -4 - 2
0 ≥ -6

Answer 6

So it's D1?

Answer 7

(-4)(-1) = 4
When you multiply or divide numbers, two positives or two negatives make a positive. A negative and a positive make a negative.

Answer 8

0 ≥ 4 - 2
0 ≥ 2

So it's A1?

Answer 9

And B2?

Answer 10

I got full points for both guesses! Thank you so much! (A1 and B2)

Answer 11

Correct