Question

What is the quotient in simplified form? State any restrictions on the variable.

Answer 1

\[\frac{ x^2 - 16 }{ x^2 + 5x + 6 } \div \frac{ x^2 + 5x + 4 }{ x^2 - 2x - 8 }\]

Answer 2

Multiple choice answers:

\[ \frac{ (x-4^2) }{ (x+3)(x+1) }\] x =/ -3 -1

\[\frac{ (x+4)^2(x+1) }{ (x+2)^2 (x+3) }\] x =/ -3, -2 4

Answer 3

\[\frac{ (x-4)^2 }{ (x+3)(x+1) }\] x=/ -4 -3 -2 -1 4

Answer 4

\[\frac{ 1 }{ (x+3(x+1) }\] x =/ -4 -3 -2 -1 4

Answer 5

ok, first use this
\(\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}\)

Answer 6

so, \(\frac{ x^2 - 16 }{ x^2 + 5x + 6 } \div \frac{ x^2 + 5x + 4 }{ x^2 - 2x - 8 }=.. ?\)

Answer 7

not required...just observe that if we change division sign to multiplication sign, the 2nd fraction flips...

Answer 8

ooooh yup i c that

Answer 9

flips means the numerator becomes denom., and denom. becomes num.

Answer 10

\(\frac{ x^2 - 16 }{ x^2 + 5x + 6 } \div \frac{ x^2 + 5x + 4 }{ x^2 - 2x - 8 }=.. ?\)

Answer 11

I have to find out what it equals?

Answer 12

how would i start doing that?

Answer 13

i meant , from the above explanation,

\(\large \frac{ x^2 - 16 }{ x^2 + 5x + 6 } \div \frac{ x^2 + 5x + 4 }{ x^2 - 2x - 8 }=\frac{ x^2 - 16 }{ x^2 + 5x + 6 } \times \frac{ x^2 - 2x - 8}{ x^2 + 5x + 4 }\)
got this ?

Answer 14

yup got it

Answer 15

now do you also need help factoring those 4 expressions ?

Answer 16

oh yeasss

Answer 17

or can you factor by yourself ?

Answer 18

\(x^2-16= x^2-4^2=(x+4)(x-4) \\as, a^2-b^2=(a+b)(a-b)\)

Answer 19

As a wild guess I think its A

Answer 20

its C.
-4 -3 -2 -1 4