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How can I differentiate this function. P=5Qe-0.1Q?
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you want to do dP/dQ?
You will need the product rule, \[\frac{ d(f(x)g(x) }{ dx }=f'(x)g(x)+g'(x)f(x)\]
Yes i need dp/dq
so dP/dQ=5e^-0.1Q-0.5Qe^-0.1Q
Is it possible to find the value of Q if I were to equate the derivative to Zero?
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yes it is
Is it 10?
1 second Ill have a pop
is P = 5Qe^0.1Q ?
P=5Qe^-0.1Q
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Indeed it is 10, well done =)
Thanks
oh ok.now i get it
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