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Mathematics 15 Online
OpenStudy (anonymous):

How can I differentiate this function. P=5Qe-0.1Q?

OpenStudy (anonymous):

you want to do dP/dQ?

OpenStudy (anonymous):

You will need the product rule, \[\frac{ d(f(x)g(x) }{ dx }=f'(x)g(x)+g'(x)f(x)\]

OpenStudy (anonymous):

Yes i need dp/dq

OpenStudy (anonymous):

so dP/dQ=5e^-0.1Q-0.5Qe^-0.1Q

OpenStudy (anonymous):

Is it possible to find the value of Q if I were to equate the derivative to Zero?

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

Is it 10?

OpenStudy (anonymous):

1 second Ill have a pop

OpenStudy (anonymous):

is P = 5Qe^0.1Q ?

OpenStudy (anonymous):

P=5Qe^-0.1Q

OpenStudy (anonymous):

Indeed it is 10, well done =)

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

oh ok.now i get it

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