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Mathematics 13 Online
OpenStudy (anonymous):

First person to solve: Medal & I'll become your fan. Please help.

OpenStudy (anonymous):

OpenStudy (anonymous):

Do you know how to solve an annulus?

OpenStudy (anonymous):

no.

OpenStudy (anonymous):

c

OpenStudy (anonymous):

You have to find the area of the whole circle, and substract it from the area of the small circle

OpenStudy (anonymous):

The diameter of the whole circle is 5, so pi5^2= 25pi

OpenStudy (anonymous):

Sorry I meant radius up there not diameter. The radius of the small circle is 3. So again 3^2pi = 9pi

OpenStudy (anonymous):

So 25 - 9 leaves 16Pi

OpenStudy (anonymous):

Yeah she's right i didn't do the hole problem

OpenStudy (anonymous):

16 * 3.14 = ?

OpenStudy (anonymous):

50.24

OpenStudy (anonymous):

wth. it's not an answer choice. hold on let me redo it on paper.

OpenStudy (anonymous):

hmm...

OpenStudy (anonymous):

Oh, It's only asking for the area of the whole circle. So just add the diameter of both of them 3+ 2 and the answer is 25pi so its 78.5

OpenStudy (anonymous):

Radius* again

OpenStudy (anonymous):

gj doe!

OpenStudy (anonymous):

thank you! (:

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