Question

Write the quadratic function in vertex form.
y = x^2 + 4x + 7

Answer 1

first coordinate of the vertex is always \(-\frac{b}{2a}\) which in your case is
\[-\frac{4}{2}=-2\] so start with
\[y=(x+2)^2+k\] and to find \(k\) replace \(x\) by \(-2\) and see what you get

Answer 2

@satellite73 I got: y = 0 + k

I'm sort of confused, because here are my answer choices:

y = (x + 2)^2 + 3

y = (x + 2)^2 - 3

y = (x - 2)^2 - 3

y = (x - 2)^2 + 3

Answer 3

@satellite73 Can you help me please??? (: