Question

Help please
factoring 27x^2+18x+3

Answer 1

a common factor is 3:

3(9x^2 + 6x + 1)


Now we have to factorize (9x^2 + 6x + 1)

we have to find something in the form of this:

(ax + b)(cx + d)

I don't know what method you use, but we know that db = 1 (because the constant term is 1) and ac = 9. We also know ad + bc = 6

Now using inspection etc we get:

3(3x + 1)^2

Answer 2

first of all the equation must be equated to zero for factorising.
on equating it to zero and solving we get x=-1/3

Answer 3

hars.hit, that's completely wrong. There's a difference between solving and factorising. factorising can be done to expressions.

Answer 4

u too have done it

Answer 5

no. i have not.