OpenStudy (anonymous):
Express the concentration of a .0880M aqueous solution of fluoride in mass percentage. assume the denisty is 1.00g/ml.
OpenStudy (anonymous):
okey dokey. Using our handy dandy molarity equation we'll find the amount of moles of fluoride in the solution. We'll just assume one liter \[molarity = \frac{moles}{liters}\]that gives us .0880 moles of fluoride per 1L and since we know there is 1.00 g for every one ml from the density given, we can say that 1 liter or 1000ml of this solution weighs 1000g. now we just convert the moles of fluoride to grams using the molar mass equation which I'm going to assume you know how to do. Then all you gotta do is divide the amount fluoride in grams by the total weight which is 1000g. Then multiply by 100% and wala! you have the answer in a percentage. Let me know if you have any questions.
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