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OpenStudy (anonymous):
if graphing and factoring are applied to solve x^2+6x=-9, what could be the solution?
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OpenStudy (anonymous):
Another question, What could be the value of C that makes r^2-9r+C a perfect square?
OpenStudy (anonymous):
?????????????
OpenStudy (unklerhaukus):
?=
OpenStudy (anonymous):
what is the answer?
OpenStudy (unklerhaukus):
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OpenStudy (unklerhaukus):
|dw:1359880961188:dw|
OpenStudy (anonymous):
is that AC test?
OpenStudy (unklerhaukus):
\[(x+a)^2=x^2+xa+ax+a^2=x^2+2ax+a^2\]
OpenStudy (anonymous):
so the answer is +3?
OpenStudy (unklerhaukus):
yes \(x=3\) is the solution to the first equation
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OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
What could be the value of C that makes r^2-9r+C a perfect square?
OpenStudy (unklerhaukus):
its a perfect square when\[r^2-9r+C=0\]\[r^2-2\times\frac92r+\sqrt C^2=0\]
OpenStudy (kropot72):
The answer to the first question is x = -3.
OpenStudy (unklerhaukus):
your right @kropot72
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OpenStudy (kropot72):
Cool :)
OpenStudy (unklerhaukus):
we found \[(x+3)^2=0\]for this to be true \(x=-3\) (not +3)
OpenStudy (anonymous):
please simplify the answer in the second question
i cannot understand
OpenStudy (kropot72):
This is a partial graph of y = x^2 + 6x + 9 to give a graphical solution to the first question.
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