An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge density σ1 = 0.3 μC/m2. Another infinite sheet of charge with uniform charge density σ2 = -0.33 μC/m2 is located at x = c = 21.0 cm.. An uncharged infinite conducting slab is placed halfway in between these sheets ( i.e., between x = 8.5 cm and x = 12.5 cm).

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anonymous · Answer

https://www.smartphysics.com/Content/Media/Images/EM/06/h6_planeA.png (picture)

anonymous · Answer

What is V(S) - V(P), the potentital difference between point P and point S, located at (x,y) = (16.75 cm, -12.5 cm)?

anonymous · Answer

I know that the thick slab can be basically ignored since it has a net charge of 0.

anonymous · Answer

I was able to find the e field at P which is 35593.2 N/C. I know that V(p) is equal to V(R). I think i'm struggling with how to get V. I know that V=-integral of E..but i'm not quite sure how to go about this

anonymous · Answer

@JamesJ any suggestions?

anonymous · Answer

@zepdrix any ideas?

anonymous · Answer

@radar help?