I believe I did this right, but my teacher says its wrong. Can you show me where I went wrong?
hm so what is the actual question?
\[\frac{ \sin }{ 1-\cos }+\frac{ \sin }{ 1+\cos }=2\csc\]
for the second step I got \[\frac{ \sin+\cos \times \sin }{ 1-\cos^2 }+\frac{ \sin-\cos \times \sin }{ 1-\cos^2 }\]
yeah not bad go one
\[\frac{ 2\sin }{ 1-\cos^2 }\]
go on
\[\frac{ 2\sin }{ \sin^2 }\]
yeah
\[\frac{ 2 }{ \sin }\]
thats it
\[2\csc=2\csc\]
correct whats wrong in this
alright my teacher put a note saying: "This one should begin by finding common denominators and combing the fractions. " so I am confused because I did find a common dendominator
maybe the common denominator is (1-cos2) and u hve done it right..
alright well thank you. I will ahve to call her.
maybe when combining denominator..it has to be one u hve put it in both sides the (1-cos2) it has to be a whole (1-cos 2 )
\[\frac{1}{1+\cos} + \frac{1}{1-\cos} = \frac{1(1-\cos)+1(1+\cos)}{1-\cos2}\]
something like this?
yes I made so that she can see where I made the factors similar. on the bottom I put 1-cos(+cos) and the other side I put 1+cos(-cos)
then u better call her xD
I will lol thanks for your help though! :)
wlcome:)
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