Question

-(27/64y to the sixth power) to the 2/3 power

Answer 1

(-(27/64 y)^6)^2/3

??

Answer 2

only one set of parentheses

Answer 3

-(26/64y)^6 <--- then ALL of that to the 2/3 power, or ^6^2/3

Answer 4

all of that to the 2/3 power
its 27 not 26

Answer 5

tomatoes, tamatoes, hold on.

Answer 6

you want to solve for y, or just simplify?

Answer 7

i keep getting it wrong

Answer 8

simplify

Answer 9

Well you can rewrite this as

\[1/3(-(27y/64)^6)^2\]

Answer 10

ok

Answer 11

only 64y has the sixth power by the way. sorry

Answer 12

\[-(27/64y^6)^2/3\]

Answer 13

the question is:Simplify the expression. The variable represents a positive real number.

Answer 14

^2/3

Answer 15

like that?

Answer 16

yup

Answer 17

then you can rewrite that as
-1/3((27)/(64y^6))^2

= -243 / 4096y^12

Answer 18

that was wrong, i think they are looking for a radical

Answer 19

bump your question, because that's how i would have simplified it.

Answer 20

okay, maybe this what they mean if they are looking for a radical

-(27/64y^6)^3 = \[- \sqrt[3]{729 / 4096y^(12)} = -9/4096y^4\]19683 / 262144y^10

Answer 21

oops, ignore the last part with 19683

Answer 22

by the way, are you sure you entered the first answer correctly? because that should be right.