(x+2/x)/(3+4/x)=5x
\[\dfrac{ \dfrac{ \dfrac{ x+2 }{ x } }{ 3+4 } }{ x }=5x\] \[\dfrac{ \dfrac{ \dfrac{ x+2 }{ x } }{ 7 } }{ x }=5x\] \[\dfrac{x+2}{x}\times \dfrac{x}{7}=5x\] \[\dfrac{x+2}{7}=5x\] \[\dfrac{x+2}{7} \times 7=5x\times 7\] \[x+2=35x\]
the book has \[(-5\pm4\sqrt{2})/7\]
Because I'm sure you wrote the wrong question down in the second term. In your numerator it says 3+4. It probably is x+4 for 3+x. or something like that. (x+2/x)/(3+4/x)=5x
x+4 or 3+x*
{x = -5/7+(4/7)*sqrt(2)}, {x = -5/7-(4/7)*sqrt(2)}
use wolfram alpha
@timo86m Dude, the question was written incorrectly. That would just find a quadratic equation and then you wouldn't know where that came from that question above.
Her q would definately be a quadratic. However how are we suppose to know what she means?
...Mate, she's offline...As good as wolfram alpha is, you ain't gonna know what she means unless she comes back with the correct question. That's why it's no use telling her to go to wolfram alpha.
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